📄 getTypeName.js
/home/palash/git/site/node_modules/@typescript-eslint/type-utils/dist/getTypeName.js
Language: js • Lines: 74
"use strict";
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var __setModuleDefault = (this && this.__setModuleDefault) || (Object.create ? (function(o, v) {
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var __importStar = (this && this.__importStar) || function (mod) {
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Object.defineProperty(exports, "__esModule", { value: true });
exports.getTypeName = void 0;
const ts = __importStar(require("typescript"));
/**
 * Get the type name of a given type.
 * @param typeChecker The context sensitive TypeScript TypeChecker.
 * @param type The type to get the name of.
 */
function getTypeName(typeChecker, type) {
    // It handles `string` and string literal types as string.
    if ((type.flags & ts.TypeFlags.StringLike) !== 0) {
        return 'string';
    }
    // If the type is a type parameter which extends primitive string types,
    // but it was not recognized as a string like. So check the constraint
    // type of the type parameter.
    if ((type.flags & ts.TypeFlags.TypeParameter) !== 0) {
        // `type.getConstraint()` method doesn't return the constraint type of
        // the type parameter for some reason. So this gets the constraint type
        // via AST.
        const symbol = type.getSymbol();
        const decls = symbol === null || symbol === void 0 ? void 0 : symbol.getDeclarations();
        const typeParamDecl = decls === null || decls === void 0 ? void 0 : decls[0];
        if (ts.isTypeParameterDeclaration(typeParamDecl) &&
            typeParamDecl.constraint != null) {
            return getTypeName(typeChecker, typeChecker.getTypeFromTypeNode(typeParamDecl.constraint));
        }
    }
    // If the type is a union and all types in the union are string like,
    // return `string`. For example:
    // - `"a" | "b"` is string.
    // - `string | string[]` is not string.
    if (type.isUnion() &&
        type.types
            .map(value => getTypeName(typeChecker, value))
            .every(t => t === 'string')) {
        return 'string';
    }
    // If the type is an intersection and a type in the intersection is string
    // like, return `string`. For example: `string & {__htmlEscaped: void}`
    if (type.isIntersection() &&
        type.types
            .map(value => getTypeName(typeChecker, value))
            .some(t => t === 'string')) {
        return 'string';
    }
    return typeChecker.typeToString(type);
}
exports.getTypeName = getTypeName;
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